A shaft has two heavy rotors mounted on it. The transverse natural frequencies, considering each of the rotor separately, are 100 Hz and 200 Hz respectively. The lowest critical speed is
A. 5,367 r.p.m.
B. 6,000 r.p.m.
C. 9,360 r.p.m.
D. 12,000 r.p.m.
Answer: Option A
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When two shafts 100+200 hz = 60 rpm * 60 (2).
rpm = 7200.
rpm the transverse natural frequency 1.35 to 1.5,
7200/1.3 =5367 rpm.
(1/f)=(1/10000)+(1/40000)
f=89.44hz
n=89.44*60
=5367rpm