A shaft of diameter D is subjected to a twisting moment (T) and a bending moment (M). If the maximum bending stress is equal to maximum shear stress developed, then M is equal to
A. $$\frac{{\text{T}}}{2}$$
B. T
C. 2T
D. 4T
Answer: Option A
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Related Questions on Strength of Materials in ME
A. Equal to
B. Less than
C. Greater than
D. None of these
A. $$\frac{{{\text{w}}l}}{6}$$
B. $$\frac{{{\text{w}}l}}{3}$$
C. $${\text{w}}l$$
D. $$\frac{{2{\text{w}}l}}{3}$$
The columns whose slenderness ratio is less than 80, are known as
A. Short columns
B. Long columns
C. Weak columns
D. Medium columns
Maximum Bending stress due to bending moment: 32M/pid³
Maximum Shear stress due to twisting moment/ torque: 16T/,pid³
As both r equal So by Solving above two we get
M,= 1/2