# A shopkeeper first raises the price of Jewellery by x% then he decreases the new price by x%. After such up down cycle, the price of a Jewellery decreased by Rs. 21025. After a second up down cycle the Jewellery was sold for Rs. 484416. What was the original price of the jewellery.

A. Rs. 5,26,000

B. Rs. 6,00,625

C. Rs. 5,25,625

D. Rs. 5,00,000

E. None of these

**Answer: Option C **

__Solution(By Examveda Team)__

Let the initial price = Rs. 10000pPrice after first increment = 10000p + 100xp

Price after first decrement

= 10000p + 100xp - (100px + px

^{2})

= 10000p - px

^{2}

Now, total decrement, px

^{2}= 21025 . . . . . (1)

Price after second increment,

= 10000p - px

^{2}+ 100xp - $$\frac{{{\text{p}}{{\text{x}}^3}}}{{100}}$$

Price after second increment,

= 10000p - p

^{2}+ 100xp - $$\frac{{{{\text{p}}^3}}}{{100}}$$ - 100xp + $$\frac{{{\text{p}}{{\text{x}}^3}}}{{100}}$$ - px

^{2}+ $$\frac{{{\text{p}}{{\text{x}}^4}}}{{10000}}$$

= 10000p - 2px

^{2}+ $$\frac{{{\text{p}}{{\text{x}}^2}}}{{10000}}$$

= 484416 . . . . . . (2)

On solving equation (1) and (2), We get

x = 20

Substituting back we get,

p = 5,25,625

Related Questions on Percentage

A. $$\frac{1}{4}$$

B. $$\frac{1}{3}$$

C. $$\frac{1}{2}$$

D. $$\frac{2}{3}$$

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