A signals m(t) with bandwidth 500 Hz is first multiplied by a signal g(t) where $$g\left( t \right) = \sum\limits_{k = - \infty }^\infty {{{\left( { - 1} \right)}^k}\delta \left( {t - 0.5 \times {{10}^{ - 4}}k} \right)} $$
The resulting signal is then passed through an ideal low pass filter with bandwidth 1 kHz. The output of the low pass filter would be
A. δ(t)
B. m(t)
C. 0
D. m(t) δ(t)
Answer: Option C
This Question Belongs to Electronics And Communications Engineering >> Signal Processing
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