A speaks truth in 75% of cases and B in 80% of cases. In what percent of cases are they likely to contradict each other in narrating the same event?

A. 35%

B. 5%

C. 45%

D. 22.5%

Answer: Option A

Solution(By Examveda Team)

Different possible cases of contradiction,
A speaks truth and B does not speaks truth.
Or, A does not speak truth and B speaks truth.
$$\eqalign{ & = \left( {\frac{3}{4} \times \frac{1}{5}} \right) + \left( {\frac{1}{4} \times \frac{4}{5}} \right) \cr & = \frac{3}{{20}} + \frac{4}{{20}} \cr & = \frac{7}{{20}} \cr & = 35\% \cr} $$