A spider climbed $$\frac{{125}}{2}$$ % of the height of the pole in one hour and in the next hour it covered $$\frac{{25}}{2}$$ % of remaining height. If pole's height is 192 m, then distance climbed in second hour is:
A. 3m
B. 5m
C. 7m
D. 9m
Answer: Option D
Solution(By Examveda Team)
$$\eqalign{ & {\text{Height}}\,{\text{of}}\,{\text{the}}\,{\text{Pole}} = 192\,m. \cr & {\text{Spider}}\,{\text{covered}}\,{\text{in}}\,{\text{first}}\,{\text{hour}}, \cr & = \frac{{125}}{2}\% \,of\,192 \cr & = \frac{{ {125 \times 192} }}{{ {2 \times 100} }} \cr & = 120\,m \cr & {\text{Remaining Pole}} = 192 - 120 = 72\,m \cr & {\text{Spider}}\,{\text{covered}}\,{\text{in}}\,{\text{second}}\,{\text{hour}}, \cr & = \frac{{25}}{2}\% \,{\text{of}}\,{\text{ remaining}}\,{\text{ height}} \cr & = \frac{{ {25 \times 72} }}{{ {2 \times 100} }} \cr & = 9\,m \cr} $$Join The Discussion
Comments ( 1 )
Related Questions on Percentage
A. $$\frac{1}{4}$$
B. $$\frac{1}{3}$$
C. $$\frac{1}{2}$$
D. $$\frac{2}{3}$$
62 /2%=5/8
Left=1-5/8=3/8
12.5%=1/8
3/8. 1/8 192=9