A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly?
A. 12
B. 16
C. 24
D. 18
Answer: Option B
Solution (By Examveda Team)
Let he has solved correctly X no. of sums. Therefore incorrect no. of sums = 2X Now, X + 2X = 48 3X = 48 X = 16 sums he has done correctly.This Question Belongs to Arithmetic Ability >> Number System
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