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This question belongs to Arithmetic Ability Number System

Number System

?

A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly?

A) 12 B) 16 C) 24 D) 18

Answer & Solution

Correct Answer: Option B

Let he has solved correctly X no. of sums. Therefore incorrect no. of sums = 2X
Now,
X + 2X = 48
3X = 48
X = 16 sums he has done correctly.

Question posted by Examveda

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