A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly?
A. 12
B. 16
C. 24
D. 18
Answer: Option B
Solution(By Examveda Team)
Let he has solved correctly X no. of sums. Therefore incorrect no. of sums = 2X Now, X + 2X = 48 3X = 48 X = 16 sums he has done correctly.Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
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