A student multiplied a number with $$\frac{3}{4}$$ instead of $$\frac{4}{3}.$$ What is the error percentage?

$$\eqalign{ & \frac{3}{4},\,\frac{4}{3} \cr & {\text{LCM of 4, 3}} = 12 \cr & {\text{First number}} \cr & = \frac{3}{4} \times 12 = 9 \cr & {\text{Second number}} \cr & = \frac{4}{3} \times 12 = 16 \cr & {\text{Error percentage}} \cr & = \frac{7}{{16}} \times 100 = 43\frac{3}{4}\% = 43.75\% \cr} $$