A student multiplied a number with $$\frac{3}{4}$$ instead of $$\frac{4}{3}.$$ What is the error percentage?
A. 59.67%
B. 43.75%
C. 67.45%
D. 39.34%
Answer: Option B
Solution(By Examveda Team)
$$\eqalign{ & \frac{3}{4},\,\frac{4}{3} \cr & {\text{LCM of 4, 3}} = 12 \cr & {\text{First number}} \cr & = \frac{3}{4} \times 12 = 9 \cr & {\text{Second number}} \cr & = \frac{4}{3} \times 12 = 16 \cr & {\text{Error percentage}} \cr & = \frac{7}{{16}} \times 100 = 43\frac{3}{4}\% = 43.75\% \cr} $$Related Questions on Percentage
A. $$\frac{1}{4}$$
B. $$\frac{1}{3}$$
C. $$\frac{1}{2}$$
D. $$\frac{2}{3}$$
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