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A student took five papers in an examination, where the full marks were the same for each paper. His marks in these papers were in the proportion of 6:7:8:9:10. In all papers together, the candidate obtained 60% of the total marks then, the number of papers in which he got more than 50% marks is

A. 1

B. 3

C. 4

D. 5

E. None of these

Answer: Option C

Solution(By Examveda Team)

Let the marks obtained in five subjects be 6x, 7x, 8x, 9x and 10x.
Total marks obtained = 40x
Max. Marks of the five subjects = $$\frac{{40{\text{x}}}}{{0.6}}$$   [40x is 60% of total marks]
Max. Marks in each subject = $$\frac{{40{\text{x}}}}{{0.6 \times 5}}$$   = 13.33x
Hence, % of each subject = $$\frac{{6{\text{x}} \times 100}}{{13.33}}$$   = 45.01%
Or, $$\frac{{7{\text{x}} \times 100}}{{13.33}}$$   = 52.51
In same way other percentage are 60.01%, 67.52%, 75.01%.
Hence, number of subjects in which he gets more than 50% marks = 4

This Question Belongs to Arithmetic Ability >> Percentage

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