A sum of money placed at compound interest doubles itself in 4 years. In how many years will it amount to 8 times?
A. 9 years
B. 8 years
C. 27 years
D. 12 years
Answer: Option D
A. 9 years
B. 8 years
C. 27 years
D. 12 years
Answer: Option D
Find the simple interest on Rs. 5200 for 2 years at 6% per annum.
A. Rs. 450
B. Rs. 524
C. Rs. 600
D. Rs. 624
Rs. 1200 is lent out at 5% per annum simple interest for 3 years. Find the amount after 3 years.
A. Rs. 1380
B. Rs. 1290
C. Rs. 1470
D. Rs.1200
E. Rs. 1240
Interest obtained on a sum of Rs. 5000 for 3 years is Rs. 1500. Find the rate percent.
A. 8%
B. 9%
C. 10%
D. 11%
E. 12%
Rs. 2100 is lent at compound interest of 5% per annum for 2 years. Find the amount after two years.
A. Rs. 2300
B. Rs. 2315.25
C. Rs. 2310
D. Rs. 2320
E. None of these
Trick: Time= (2) ^ 3=4
There for 3*4=12 years
2 times ---------- 4
8times (2^3)----- 4*3
Ans. 12 years
100------->200 in 4 years
200------->400 in again 4 years then,
400------->800 in 4 years again, thus
the time becomes= 4+4+4= 12 years.
Simplest way to solve.
Thank me later😉
formula: n2=n1^(t2/t1)
n=number of times
t=years
n2 = 8 i.e. 2^3
n1 = 2 (doubles)
t2 = x
t1 = 4
n2=n1^(t2/t1)
2^3 = 2^(x/4)
3 = x/4
3*4 = x
12 = x
Sir I have doubt in this question that The time in which a sum of money will be double at 5%p.a. C.I is
If some amount of money is taken twice in 3 years, then how many years it is in 8 times?
How to solve it?
In what time will a sum of money double itself at 5% compound intrest?