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Examveda

A sum of money placed at compound interest doubles itself in 4 years. In how many years will it amount to 8 times?

A. 9 years

B. 8 years

C. 27 years

D. 12 years

Answer: Option D

Solution(By Examveda Team)

$$\eqalign{ & {\text{Let}}, \cr & {\text{Principal}} = Rs.\,100 \cr & {\text{Amount}} = Rs.\,200 \cr & {\text{Rate}} = r\% \cr & {\text{Time}} = 4\,{\text{years}} \cr & {\text{Now}}, \cr & A = P \times {\left[ {1 + \left( {\frac{r}{{100}}} \right)} \right]^n} \cr & 200 = 100 \times {\left[ {1 + \left( {\frac{r}{{100}}} \right)} \right]^4} \cr & 2 = {\left[ {1 + \left( {\frac{r}{{100}}} \right)} \right]^4} - - - - - - \left( i \right) \cr & {\text{If}}\,{\text{sum}}\,{\text{become}}\,{\text{8}}\,{\text{times}}\,{\text{in}}\,{\text{the}}\,{\text{time}}\,n\,{\text{years}} \cr & {\text{then,}} \cr & 8 = {\left( {1 + \left( {\frac{r}{{100}}} \right)} \right)^n} \cr & {2^3} = {\left( {1 + \left( {\frac{r}{{100}}} \right)} \right)^n} - - - - - - \left( {ii} \right) \cr & {\text{Using}}\,{\text{eqn}}\,\left( i \right)in\left( {ii} \right),\,{\text{we}}\,{\text{get}} \cr & {\left( {{{\left[ {1 + \left( {\frac{r}{{100}}} \right)} \right]}^4}} \right)^3} = {\left( {1 + \left( {\frac{r}{{100}}} \right)} \right)^n} \cr & {\left[ {1 + \left( {\frac{r}{{100}}} \right)} \right]^{12}} = {\left( {1 + \left( {\frac{r}{{100}}} \right)} \right)^n} \cr & {\text{Thus}},\,n = 12\,{\text{years}}. \cr} $$

This Question Belongs to Arithmetic Ability >> Interest

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Comments ( 7 )

  1. Linus Syngkli
    Linus Syngkli :
    4 years ago

    Trick: Time= (2) ^ 3=4
    There for 3*4=12 years

  2. Nithin Emmanuel
    Nithin Emmanuel :
    5 years ago

    2 times ---------- 4
    8times (2^3)----- 4*3
    Ans. 12 years

  3. Anshul Sharma
    Anshul Sharma :
    5 years ago

    100------->200 in 4 years
    200------->400 in again 4 years then,
    400------->800 in 4 years again, thus
    the time becomes= 4+4+4= 12 years.
    Simplest way to solve.
    Thank me later😉

  4. Divya Naik
    Divya Naik :
    6 years ago

    formula: n2=n1^(t2/t1)
    n=number of times
    t=years

    n2 = 8 i.e. 2^3
    n1 = 2 (doubles)
    t2 = x
    t1 = 4
    n2=n1^(t2/t1)
    2^3 = 2^(x/4)

    3 = x/4
    3*4 = x
    12 = x


  5. Sanghvi Bansod
    Sanghvi Bansod :
    7 years ago

    Sir I have doubt in this question that The time in which a sum of money will be double at 5%p.a. C.I is

  6. Karan Mehara
    Karan Mehara :
    7 years ago

    If some amount of money is taken twice in 3 years, then how many years it is in 8 times?

    How to solve it?

  7. Abhishekh Kumar
    Abhishekh Kumar :
    7 years ago

    In what time will a sum of money double itself at 5% compound intrest?

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