Examveda

A superheterodyne receiver with an IF of 450 kHz is tuned to a signal at 1200 kHz. The image frequency is

A. 750 kHz

B. 900 kHz

C. 1650 kHz

D. 2100 kHz

Answer: Option D

Solution (By Examveda Team)

Superheterodyne Receiver: A superheterodyne receiver is a type of radio receiver that uses a mixer to convert a radio frequency (RF) signal to a fixed intermediate frequency (IF). This IF signal is then amplified and demodulated to extract the audio signal.

Intermediate Frequency (IF): The intermediate frequency (IF) is a fixed frequency to which the received radio frequency (RF) signal is converted in a superheterodyne receiver. This allows for efficient amplification and filtering of the signal before demodulation.

Image Frequency: The image frequency is an unwanted signal that can also produce the same IF frequency as the desired signal. It occurs because the mixer in a superheterodyne receiver is essentially a non-linear device which produces sum and difference frequencies. The image frequency is always offset from the desired signal frequency by twice the IF.

Calculating Image Frequency: In this question, the desired RF signal is at 1200 kHz, and the IF is 450 kHz. The image frequency (fimage) can be calculated using the following formula:

fimage = fRF ± 2 * fIF

Where:
fRF is the radio frequency (1200 kHz)
fIF is the intermediate frequency (450 kHz)

Using the formula:

fimage = 1200 kHz + 2 * 450 kHz = 2100 kHz
or
fimage = 1200 kHz - 2 * 450 kHz = 300 kHz (This is not among the options)

Therefore, the image frequency is 2100 kHz (Option D).


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Comments (3)

  1. Anuj Dhumal
    Anuj Dhumal:
    3 years ago

    Fsi =fs +2IF

  2. Seshunadh Gattim
    Seshunadh Gattim:
    5 years ago

    How

  3. Mohammed Ali
    Mohammed Ali:
    5 years ago

    how to get above answer

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