A tank of uniform cross-sectional area (A) containing liquid upto height (H1) has an orifice of cross-sectional area (a) at its bottom. The time required to bring the liquid level from H1 to H2 will be

2A( sqrt H_1 - sqrt H_2 )C_d asqrt 2g

This question belongs to Mechanical Engineering Hydraulics And Fluid Mechanics In ME

Hydraulics and Fluid Mechanics in ME

A tank of uniform cross-sectional area (A) containing liquid upto height (H₁) has an orifice of cross-sectional area (a) at its bottom. The time required to bring the liquid level from H₁ to H₂ will be

A) $$\frac{{2{\text{A}}\sqrt {{{\text{H}}_1}} }}{{{{\text{C}}_{\text{d}}} \times {\text{a}}\sqrt {2{\text{g}}} }}$$ B) $$\frac{{2{\text{A}}\sqrt {{{\text{H}}_2}} }}{{{{\text{C}}_{\text{d}}} \times {\text{a}}\sqrt {2{\text{g}}} }}$$ C) $$\frac{{2{\text{A}}\left( {\sqrt {{{\text{H}}_1}} - \sqrt {{{\text{H}}_2}} } \right)}}{{{{\text{C}}_{\text{d}}} \times {\text{a}}\sqrt {2{\text{g}}} }}$$ D) $$\frac{{2{\text{A}}\left( {{\text{H}}_1^{\frac{3}{2}} - {\text{H}}_2^{\frac{3}{2}}} \right)}}{{{{\text{C}}_{\text{d}}} \times {\text{a}}\sqrt {2{\text{g}}} }}$$

Answer & Solution

Correct Answer: Option C

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