A transformer has a 1:6 turns ratio and a secondary coil load resistance of 470 Ω. The load resistance as seen by the source is

Solution (By Examveda Team)

Here's an explanation to help you understand how to solve this transformer question:

The question involves the concept of the turns ratio of a transformer and how it relates to the impedance transformation.

Turns Ratio (N1:N2): In this problem, the turns ratio is given as 1:6. This means for every 1 turn in the primary coil, there are 6 turns in the secondary coil. We can represent this as N1/N2 = 1/6.

Impedance Transformation: A transformer changes the apparent impedance (resistance in this case) seen by the source (primary side). The relationship is:

Z1 = (N1/N2)^2 * Z2

Where:
Z1 is the impedance seen by the source (primary side).
Z2 is the impedance of the load connected to the secondary side.
N1/N2 is the turns ratio.

In our problem:
N1/N2 = 1/6
Z2 = 470 Ω

Now, let's calculate Z1:
Z1 = (1/6)^2 * 470
Z1 = (1/36) * 470
Z1 ≈ 13.05 Ω

Therefore, the load resistance as seen by the source is approximately 13 Ω.

So the correct answer is Option D: 13 Ω