A uniform body 3 m long, 2 m wide and 1 m deep floats in water. If the depth of immersion is 0.6 m, then the weight of the body is
A. 3.53 kN
B. 33.3 kN
C. 35.3 kN
D. None of these
Answer: Option C
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Related Questions on Hydraulics and Fluid Mechanics in ME
A flow in which the quantity of liquid flowing per second is constant, is called __________ flow.
A. Steady
B. Streamline
C. Turbulent
D. Unsteady
A hydraulic ram is a device used to
A. Store the energy of water
B. Increase the pressure of water
C. To lift water from deep wells
D. To lift small quantity of water to a greater height when a large quantity of water is available at a smaller height
A. The weight of the body
B. More than the weight of the body
C. Less than the weight of the body
D. Weight of the fluid displaced by the body
@madhavan Fb= Specific weight of liquid (9.81KN/m3) * Volume of immersion (2x3x0.6 m3)
At equilibrium, weight of body (W) = Force of buoyancy (Fb).
Fb = Specific gravity * Volume of immersion.
Fb = 9.81*1000*0.6*2*3.
Fb = 35.3 KN.
Hence weight of body = 35.3 KN.