ExamVeda
Login
Home
Hydraulics and Fluid Mechanics in ME
?

A uniform body 3 m long, 2 m wide and 1 m deep floats in water. If the depth of immersion is 0.6 m, then the weight of the body is

Answer & Solution
Correct Answer: Option C
Let's discuss the solution. Join the discussion
Examveda
Question posted by Examveda
Community

Join the Discussion

2 Comments
Samra Javaid
Samra Javaid 3 years ago
@madhavan Fb= Specific weight of liquid (9.81KN/m3) * Volume of immersion (2x3x0.6 m3)
Madhavan Palmani
Madhavan Palmani 7 years ago
At equilibrium, weight of body (W) = Force of buoyancy (Fb).

Fb = Specific gravity * Volume of immersion.

Fb = 9.81*1000*0.6*2*3.

Fb = 35.3 KN.

Hence weight of body = 35.3 KN.