A vessel of capacity 2 litre has 25% alcohol and another vessel of capacity 6 litre had 40% alcohol. The total liquid of 8 litre was poured out in a vessel of capacity 10 litre and thus the rest part of the vessel was filled with the water. what is the new concentration of mixture ?
A. 29%
B. 49%
C. 31%
D. 71%
E. None of these
Answer: Option A
Solution(By Examveda Team)
Amount of alcohol in first vessel, = 25% of 2 litre = 0.25 × 2 = 0.5 litre Amount of alcohol in second vessel, = 40% of 6 litre = 0.4 × 6 = 2.4 litre Total amount of alcohol out of 10 litres of mixture is 0.5 + 2.4 = 2.9 litre Thus, Concentration of the mixture is, $$\frac{{2.9 \times 100}}{{10}}$$ = 29%Related Questions on Ratio
If a : b : c = 3 : 4 : 7, then the ratio (a + b + c) : c is equal to
A. 2 : 1
B. 14 : 3
C. 7 : 2
D. 1 : 2
If $$\frac{2}{3}$$ of A=75% of B = 0.6 of C, then A : B : C is
A. 2 : 3 : 3
B. 3 : 4 : 5
C. 4 : 5 : 6
D. 9 : 8 : 10
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