A young girl counted in the following way on the fingers of her left hand. She started calling the thumb 1, the index finger 2, middle finger 3, ring finger 4, little finger 5, then reversed direction, calling the ring finger 6, middle finger 7, index finger 8, thumb 9 and then back to the index finger for 10, middle finger for 11 and so on. She counted up 1994. She ended on her
A. Thumb
B. Index finger
C. Middle finger
D. Ring finger
E. Little finger
Answer: Option C
Solution(By Examveda Team)
If the girl counts the way as given in the question,The counting serial for thumb will be 1, 9, 17, 25 . . . . . .
Hence,
Number 1992 ( as 1992 is divisible by 8, common difference of series formed by counting) will also fall on thumb.
Hence,
Number 1994 will end on her middle finger.
This Question Belongs to Arithmetic Ability >> Number System
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Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
No.. on index finger
Yes index finger is the right answer.
The thumb series is 1,9,17,25,33...
Therefore 8n+1=1994
8n=1993
remainder=1
Therefore thumb for 1993 and next one is index.
Answer is index finger .
Clearly, while counting, the numbers associated to the thumb will be : 1, 9,17, 25,.....
i.e. numbers of the form (8n + 1).
Since 1994 = 249 x 8 + 2, so 1993 shall correspond to the thumb and 1994 to the index finger.