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A young girl counted in the following way on the fingers of her left hand. She started calling the thumb 1, the index finger 2, middle finger 3, ring finger 4, little finger 5, then reversed direction, calling the ring finger 6, middle finger 7, index finger 8, thumb 9 and then back to the index finger for 10, middle finger for 11 and so on. She counted up 1994. She ended on her
Answer & Solution
Correct Answer:
Option
C
If the girl counts the way as given in the question,
The counting serial for thumb will be 1, 9, 17, 25 . . . . . .
Hence,
Number 1992 ( as 1992 is divisible by 8, common difference of series formed by counting) will also fall on thumb.
Hence,
Number 1994 will end on her middle finger.
The counting serial for thumb will be 1, 9, 17, 25 . . . . . .
Hence,
Number 1992 ( as 1992 is divisible by 8, common difference of series formed by counting) will also fall on thumb.
Hence,
Number 1994 will end on her middle finger.
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LoginTherefore 8n+1=1994
8n=1993
remainder=1
Therefore thumb for 1993 and next one is index.
Answer is index finger .
i.e. numbers of the form (8n + 1).
Since 1994 = 249 x 8 + 2, so 1993 shall correspond to the thumb and 1994 to the index finger.