ABCD is a four bar mechanism in which AB = 310 mm and CD = 450 mm. AB and CD are both perpendicular to the fixed link AD, as shown in the below figure. If the velocity of B at this condition is v. Then the velocity of C is
A. $$\frac{1}{3}$$ v
B. $$\frac{2}{3}$$ v
C. $$\frac{3}{2}$$ v
D. $$\frac{9}{4}$$ v
Answer: Option C
Solution(By Examveda Team)
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For Crank and Rocker mechanism
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Hence option (a) will be correct.
all options are wrong in this. Since crank and rocker are parallel to each other the coupler angular velocity becomes zero. So, Vb=Vc.
Vc/Vb = CD/AB.
= 450/310 AB distance is 300 it will perfectly come.
= 1.46 ~ 1.5.
= 1.5 = 3/2.
Vc = Vb*3/2.
= 3/2 Vb.