ABCD is a rectangle of which AC is a diagonal. The value of (tan² ∠CAD + 1)sin² ∠BAC is?

A. 2

B. $$\frac{1}{4}$$

C. 1

D. 0

Answer: Option C

Solution(By Examveda Team)

= (tan²α + 1 )sin²β
= (tan²45° + 1 )sin²45°
$$ = (1 + 1) {\left( {\frac{1}{{\sqrt 2 }}} \right)^2}$$
$$ = 2 \times \frac{1}{2} = 1$$