ABCD is a rectangle of which AC is a diagonal. The value of (tan2 ∠CAD + 1)sin2 ∠BAC is?
A. 2
B. $$\frac{1}{4}$$
C. 1
D. 0
Answer: Option C
Solution (By Examveda Team)
= (tan2α + 1 )sin2β
= (tan245° + 1 )sin245°
$$ = (1 + 1) {\left( {\frac{1}{{\sqrt 2 }}} \right)^2}$$
$$ = 2 \times \frac{1}{2} = 1$$
This Question Belongs to Arithmetic Ability >> Trigonometry
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