According to Bazin's formula, the discharge over a rectangular weir is $${\text{mL}}\sqrt {2{\text{g}}} \times {{\text{H}}^{\frac{3}{2}}},$$ where m is equal to
A. $$0.405 + \frac{{0.003}}{{\text{H}}}$$
B. $$0.003 + \frac{{0.405}}{{\text{H}}}$$
C. $$0.405 + \frac{{\text{H}}}{{{\text{0}}{\text{.003}}}}$$
D. $$0.003 + \frac{{\text{H}}}{{{\text{0}}.405}}$$
Answer: Option A
This Question Belongs to Mechanical Engineering >> Hydraulics And Fluid Mechanics In ME
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