According to Euler's column theory, the crippling load for a column length $$l$$ hinged at both ends, is

A) $$\frac{{{\pi ^2}{\text{E}}I}}{{{l^2}}}$$ B) $$\frac{{{\pi ^2}{\text{E}}I}}{{4{l^2}}}$$ C) $$\frac{{4{\pi ^2}{\text{E}}I}}{{{l^2}}}$$ D) $$\frac{{2{\pi ^2}{\text{E}}I}}{{{l^2}}}$$

Answer & Solution

Correct Answer: Option A

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Atif Muneer 5 years ago

Both end fixed L = l/2 and Load = pi^2 * E * I/((l/2)^2),
Both end Hinged L = l and Load = pi^2 * E * I/(l^2),

one Fixed another Hinged L = l/Root 2,
one end fixed another free L = 2 * l.

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According to Euler's column theory the crippling load for a column...

According to Euler's column theory, the crippling load for a column length $$l$$ hinged at both ends, is

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