All solutions of the equation ez = -3 are
A. z = i n π ln 3, n = ±1, ±2, . . . . . . . .
B. z = ln 3 + i(2n + 1)π, n = 0, ±1, ±2, . . . . . . . .
C. z = ln 3 + i 2nπ, n = 0, ±1, ±2, . . . . . . . .
D. z = i 3nπ, n = ±1, ± 2, . . . . . . . .
Answer: Option B


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