Alloy A contains metals x and y only in the ratio 5 : 2 and alloy B contains these metals in the ratio 3 : 4. Alloy C is prepared by mixing A and B in the ratio 4 : 5. The percentage of x in alloy C is:
A. 45
B. $$55\frac{5}{9}$$
C. $$44\frac{4}{9}$$
D. 56
Answer: Option B
Solution(By Examveda Team)
\[\begin{array}{*{20}{c}} {}&x&:&y&{} \\ {A \to }&{{5_{ \times 4}}}&:&{{2_{ \times 4}}}&{ = {7_{ \times 4}}} \\ {B \to }&{{3_{ \times 5}}}&:&{{4_{ \times 5}}}&{ = {7_{ \times 5}}} \end{array}\]$$\eqalign{ & C \to A + B \to 35 + 28 = 63 \cr & \% \,{\text{of }}x{\text{ in aloy C}} = \frac{{35}}{{63}} \times 100 = 55\frac{5}{9}\% \cr} $$
Related Questions on Ratio
If a : b : c = 3 : 4 : 7, then the ratio (a + b + c) : c is equal to
A. 2 : 1
B. 14 : 3
C. 7 : 2
D. 1 : 2
If $$\frac{2}{3}$$ of A=75% of B = 0.6 of C, then A : B : C is
A. 2 : 3 : 3
B. 3 : 4 : 5
C. 4 : 5 : 6
D. 9 : 8 : 10
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