An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m. When it is vertically at a point A on the ground a bomb is released from it. The bomb strikes the ground at point B. The distance AB is

A) 1200 m B) 0.33 km C) 3.33 km D) 33 km

Answer & Solution

Correct Answer: Option C

Let's discuss the solution. Join the discussion

Question posted by Examveda

Community

Join the Discussion

5 Comments

Join the discussion

HIMANI TAWAR 4 years ago

If distance d = speed s x time t
And d = 1960m, s = 600km/h, t =?
t = d/s
= 1960/600
= 3.3

Rushava Narayan 5 years ago

Time to reach the point B
T= √2h/g= √2*1960/9.8= 20 sec
Now distance = velocity *time=( 600*1000/3600) *20
= 3333m = 3.33km

Aditya Joseph 7 years ago

Vp-VELOCITY OF PLANE
Vp=(5/18) X Vp=16.67m/s
HORIZONTAL:
u=0,g=9.81m/s2,S=1960m
S=ut+(1/2 X g X t)
t=19.98sec
VERTICAL:
u=166.67m/s,g=0,t=19.98sec
S=ut+(1/2 X g X t)
S=3330m=3.33Km

Amit Kumar 7 years ago

It should be 2.33km

Udeme E. 8 years ago

If distance d = speed s x time t
And d = 1960m, s = 600km/h, t =?
t = d/s
= 1960/600
= 3.3

Keep Learning

An aeroplane is flying horizontally with a velocity of 600 km...

An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m. When it is vertically at a point A on the ground a bomb is released from it. The bomb strikes the ground at point B. The distance AB is

Join the Discussion

Related Questions on Physics