An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m. When it is vertically at a point A on the ground a bomb is released from it. The bomb strikes the ground at point B. The distance AB is
A. 1200 m
B. 0.33 km
C. 3.33 km
D. 33 km
Answer: Option C
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If distance d = speed s x time t
And d = 1960m, s = 600km/h, t =?
t = d/s
= 1960/600
= 3.3
Time to reach the point B
T= √2h/g= √2*1960/9.8= 20 sec
Now distance = velocity *time=( 600*1000/3600) *20
= 3333m = 3.33km
Vp-VELOCITY OF PLANE
Vp=(5/18) X Vp=16.67m/s
HORIZONTAL:
u=0,g=9.81m/s2,S=1960m
S=ut+(1/2 X g X t)
t=19.98sec
VERTICAL:
u=166.67m/s,g=0,t=19.98sec
S=ut+(1/2 X g X t)
S=3330m=3.33Km
It should be 2.33km
If distance d = speed s x time t
And d = 1960m, s = 600km/h, t =?
t = d/s
= 1960/600
= 3.3