An alloy contains the copper and aluminum in the ratio of 7 : 4 While making the weapons from this alloy, 12% of the alloy got destroyed. If there is 12 kg of aluminum in the weapon, then weight of the alloy required is :
A. 14.4 kg
B. 37.5 kg
C. 40 kg
D. 48 kg
Answer: Option B
Solution(By Examveda Team)
Copper : Aluminum = 7 : 4 Let Copper and Aluminum in the weapon be 7x and 4x respectively Given, Aluminum in weapon = 12 kg So, → 4x = 12 → x = 3 Copper = 7x = 7 × 3 = 21 Kg. Total alloy in the weapon = 12 + 21 = 33 kg But 12% alloy get destroyed in making the weapon, i.e. 88% alloy is used in the weapon, so, → 88 % alloy = 33 kg → 100 % alloy = 37.5 kgJoin The Discussion
Comments ( 4 )
Related Questions on Percentage
A. $$\frac{1}{4}$$
B. $$\frac{1}{3}$$
C. $$\frac{1}{2}$$
D. $$\frac{2}{3}$$
88% = 33kg
So,
1% = 33/88 kg
Thus,
100% = (33 *100)/88 = 37.5 Kg.
Since 88% of alloy weight as 33kg,
therefore 100% weight of allow is (100 *33 )/88 = 37.5kg
how 100%=37.5?
How is 100% alloy =37. 5