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An alloy contains the copper and aluminum in the ratio of 7 : 4 While making the weapons from this alloy, 12% of the alloy got destroyed. If there is 12 kg of aluminum in the weapon, then weight of the alloy required is :

A. 14.4 kg

B. 37.5 kg

C. 40 kg

D. 48 kg

Answer: Option B

Solution(By Examveda Team)

Copper : Aluminum = 7 : 4
Let Copper and Aluminum in the weapon be 7x and 4x respectively
Given,
Aluminum in weapon = 12 kg
So,
→ 4x = 12
→ x = 3
Copper = 7x = 7 × 3 = 21 Kg.
Total alloy in the weapon = 12 + 21 = 33 kg
But 12% alloy get destroyed in making the weapon, i.e. 88% alloy is used in the weapon, so,
→ 88 % alloy = 33 kg
→ 100 % alloy = 37.5 kg

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Comments ( 4 )

  1. Kumar Chandan
    Kumar Chandan :
    6 years ago

    88% = 33kg
    So,
    1% = 33/88 kg
    Thus,
    100% = (33 *100)/88 = 37.5 Kg.

  2. Examveda
    Examveda :
    6 years ago

    Since 88% of alloy weight as 33kg,
    therefore 100% weight of allow is (100 *33 )/88 = 37.5kg

  3. Shireen Sitara
    Shireen Sitara :
    6 years ago

    how 100%=37.5?

  4. Faraz Qureshi
    Faraz Qureshi :
    6 years ago

    How is 100% alloy =37. 5

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