An engine operates between temperatures of 900K and T1 and another engine between T2 and 400K. For both to do equal work, value of T2 will be
A. 650K
B. 600K
C. 625K
D. 700K
Answer: Option A
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both engines to do equal work.
so w1=w2
net work1= t1-t2
= 900-t2
net work2= t1-t2
= t2-400
900-t2=t2-400
1300=2t2
t2=650.
sqrt(T1*T3)
=sqrt(900*400)
=600
CORRECT Answer Is B
Explanation is T2=SQRT(900*400)=600K