ExamVeda
Login
Home
Theory of Machine
?

An engine operates between temperatures of 900K and T1 and another engine between T2 and 400K. For both to do equal work, value of T2 will be

Answer & Solution
Correct Answer: Option A
Let's discuss the solution. Join the discussion
Examveda
Question posted by Examveda
Community

Join the Discussion

3 Comments
Mani Kandan
Mani Kandan 5 years ago
both engines to do equal work.

so w1=w2

net work1= t1-t2

= 900-t2

net work2= t1-t2

= t2-400

900-t2=t2-400

1300=2t2

t2=650.
Kumar Annav
Kumar Annav 6 years ago
sqrt(T1*T3)
=sqrt(900*400)
=600
HARENDRA KUMAR
HARENDRA KUMAR 6 years ago
CORRECT Answer Is B
Explanation is T2=SQRT(900*400)=600K