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An R.C.C. beam of 6 m span is 30 cm wide and has a lever arm of 55 cm. If it carries a U.D.L. of 12 t per m and allowable shear stress is 5 kg/cm2, the beam

A. Is safe in shear

B. Is safe with stirrups

C. Is safe with stirrups and inclined bars

D. Needs revision of section

Answer: Option D


This Question Belongs to Civil Engineering >> RCC Structures Design

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Comments ( 3 )

  1. Naresh Kumar
    Naresh Kumar :
    4 years ago

    we know that moment M=V*LA where LA is liver arm (for given signs F=verticle shear force, v=horizontal shear force, x=longitudinal distance)
    now v=M/LA , also M=F*x
    shear stress S=V/(B*x)
    S=F/(B*LA)
    for question:
    S=12000*6/2*(30*55)=21.82 >8 kg/cm^2 hence unsafe

  2. Md Arshad
    Md Arshad :
    5 years ago

    Divide 12000 kg with 55*30 we will get 7.27 kg/sqcm but in question allowable shear stress is 5kg/sqcm so it will fail and section needs to be redesign.

  3. Munfed Khan
    Munfed Khan :
    5 years ago

    can any one explain this question

Related Questions on RCC Structures Design

If the shear stress in a R.C.C. beam is

A. Equal or less than 5 kg/cm2, no shear reinforcement is provided

B. Greater than 4 kg/cm2, but less than 20 kg/cm2, shear reinforcement is provided

C. Greater than 20 kg/cm2, the size of the section is changed

D. All the above