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An R.C.C. column of 30 cm diameter is reinforced with 6 bars 12 mm φ placed symmetrically along the circumference. If it carries a load of 40,000 kg axially, the stress is

A. 49.9 kg/cm2

B. 100 kg/cm2

C. 250 kg/cm2

D. 175 kg/cm2

Answer: Option A

Solution (By Examveda Team)

Given: Diameter of R.C.C. column D = 30 cm; 6 bars of 12 mm (1.2 cm) diameter; Axial load P = 40,000 kg

Gross area of column (Ag): (π/4)D2 = (π/4)(30)2 = 706.86 cm2

Area of one bar: (π/4)d2 = (π/4)(1.2)2 = 1.131 cm2 (approx.)

Total steel area (As): 6 × 1.131 = 6.786 cm2

Net concrete area (Ac): Ag − As = 706.86 − 6.786 = 700.07 cm2

Assume modular ratio (m): 15 (typical for RCC working stress method)

Transformed area carrying load: Ac + mAs = 700.07 + 15×6.786 = 801.86 cm2

Concrete stress (working): σc = P / (Ac + mAs) = 40,000 / 801.86 = 49.9 kg/cm2

Therefore, the stress is 49.9 kg/cm2 ⇒ Option A.

This Question Belongs to Civil Engineering >> RCC Structures Design

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Comments (2)

  1. Hossayn Fedayi
    Hossayn Fedayi:
    1 month ago

    Stress =Load/Ac+mAs
    Ac= 3.14 d2/4 =706.5
    Ast= 6x 3.14xd2/4 =7.065
    modular ratio m=13
    Putting Values Stress= 40000/706.5+ 13x7.065 = 50 apx =49.9

  2. Harjeet Roy
    Harjeet Roy:
    4 years ago

    Kese solve Kiya

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