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61
Asmita invest an amount of Rs. 9534 @ 4 p.c.p.a to obtain a total amount of Rs. 11442 on simple interest after a certain period. For how many years did she invest the amount to obtain the total sum?
Discuss
Answer & Solution
Answer: Option C
Solution:
$$\eqalign{ & {\text{P}} = {\text{Rs}}{\text{. 9534}} \cr & {\text{S}}{\text{.I}}{\text{.}} = {\text{Rs}}{\text{.}}\left( {{\text{11442}} - {\text{9534}}} \right) \cr & \,\,\,\,\,\,\,\,\, = {\text{Rs}}{\text{.1908}} \cr & {\text{R}} = {\text{4}}\% \cr & \therefore {\text{Time}} = \left( {\frac{{{\text{100}} \times {\text{1908}}}}{{{\text{9534}} \times {\text{4}}}}} \right){\text{years}} \cr & = \left( {\frac{{{\text{47700}}}}{{{\text{9534}}}}} \right){\text{years}} \approx {\text{5 years}} \cr} $$
62
What sum will amount to Rs. 7000 in 5 years at $${\text{3}}\frac{1}{3}$$ % simple interest ?
Discuss
Answer & Solution
Answer: Option C
Solution:
$$\eqalign{ & {\text{Amount Rs 7000}} \cr & {\text{Total interest in 5 years}} \cr & {\text{ = 5}} \times \frac{{10}}{3}\% = \frac{{50}}{3}\% = \frac{1}{6} \cr} $$
  Principal     Amount  
  6     (6 + 1)  
  ↓ × 1000     ↓ × 1000  
  6000     7000  
Hence required principal = Rs. 6000
63
Mohan lent some amount of money at 9% simple interest and an equal amount of money at 10% simple interest each for two years. If his total interest was Rs. 760, what amount was lent in each case ?
Discuss
Answer & Solution
Answer: Option D
Solution:
Let the amount invested = Rs. P
According to the questions,
$$\eqalign{ & \Leftrightarrow \frac{{{\text{P}} \times 9 \times {\text{2}}}}{{100}} + \frac{{{\text{P}} \times {\text{10}} \times {\text{2}}}}{{100}} = 760 \cr & \Leftrightarrow \frac{{ {18{\text{P + 20P}}} }}{{100}} = 760 \cr & \Leftrightarrow 38{\text{P = 76000}} \cr & \Leftrightarrow {\text{P = 2000}} \cr} $$

Alternate
Total interest percent
$$\eqalign{ & {\text{ = }}\left( {9 \times 2} \right)\% + \left( {10 \times 2} \right)\% \cr & \Rightarrow 38\% = 760 \cr & \Rightarrow 100\% = 2000 \cr} $$
Hence required principal
= Rs. 2000
64
If the simple interest on a sum of money for 15 months at $${\text{7}}\frac{1}{2}$$ % per annum exceeds the simple interest on the same sum for 8 months at $${\text{12}}\frac{1}{2}$$ % per annum by Rs. 32.50, then the sum of money ( In Rs.) is ?
Discuss
Answer & Solution
Answer: Option C
Solution:
$$\eqalign{ & {{\text{T}}_1} = 15\operatorname{months} \cr & \,\,\,\,\,\, = \frac{{15}}{{12}}years \cr & {R_1} = 7\frac{1}{2}\% = \frac{{15}}{2}\% \cr & {{\text{T}}_2} = 8\operatorname{months} \cr & \,\,\,\,\,\,\, = \frac{8}{{12}}years \cr & {{\text{R}}_2} = 12\frac{1}{2}\% = \frac{{25}}{2}\% \cr & {\text{Let the principal}} = {\text{P}} \cr & {\text{According to the question,}} \cr & \Leftrightarrow \frac{{{\text{P}} \times {\text{15}} \times {\text{15}}}}{{12 \times 2 \times 100}} - \frac{{{\text{P}} \times 25 \times 8}}{{12 \times 2 \times 100}} = 32.50 \cr & \Rightarrow \frac{{225{\text{P}}}}{{2400}} - \frac{{200{\text{P}}}}{{2400}} = 32.50 \cr & \Rightarrow \frac{{25{\text{P}}}}{{2400}} = 32.50 \cr & \Rightarrow {\text{P = Rs 3120}} \cr & {\text{Hence required principal}} \cr & {\text{ = Rs}}{\text{. 3120}} \cr} $$
65
Deepak invested an amount of Rs. 21250 for 6 years. At what rate of simple interest will be obtain the total amount of Rs. 26350 at the end of 6 years?
Discuss
Answer & Solution
Answer: Option E
Solution:
$$\eqalign{ & {\text{P}} = {\text{Rs}}{\text{.}}\,{\text{21250}} \cr & {\text{S}}{\text{.I}}{\text{.}} = {\text{Rs}}{\text{.}}\,\left( {{\text{26350}} - {\text{21250}}} \right) \cr & \,\,\,\,\,\,\,\,\,\, = {\text{Rs}}{\text{.}}\,5100 \cr & {\text{T}} = {\text{6 years}} \cr & \therefore {\text{Rate}} = \left( {\frac{{100 \times 5100}}{{{\text{21250}} \times {\text{6}}}}} \right)\% \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 4\% \cr} $$
66
At what rate of simple interest per annum can an amount of Rs. 1553.40 be obtained on the principal amount of Rs. 8630 after 3 years?
Discuss
Answer & Solution
Answer: Option E
Solution:
$$\eqalign{ & {\text{P}} = {\text{Rs.}}{\text{ 8630}} \cr & {\text{S}}{\text{.I}}{\text{.}} = {\text{Rs.}}{\text{ 1553}}{\text{.40}} \cr & {\text{T}} = {\text{3 years}} \cr & \therefore {\text{Rate}} \cr & = \left( {\frac{{100 \times 1553.40}}{{8630 \times 3}}} \right)\% \cr & = 6\% \cr} $$
67
If simple interest on Rs. 600 for 4 years and on Rs. 600 for 2 years combined together is Rs.180, find the rate of interest.
Discuss
Answer & Solution
Answer: Option B
Solution:
$$\eqalign{ & {\text{Let the rate of be R}}\% {\text{p}}{\text{.a}}{\text{.}} \cr & Then, \cr & {\frac{{600 \times R \times 4}}{{100}}} + {\frac{{600 \times R \times 2}}{{100}}} = 180 \cr & \Rightarrow 2400{\text{R}} + 1200{\text{R}} = 18000 \cr & \Rightarrow 3600{\text{R}} = 18000 \cr & \Rightarrow {\text{R}} = 5\% \cr} $$
68
A certain sum of money becomes three times of itself in 20 years at simple interest. In how many years does it become double itself at the same rate of simple interest ?
Discuss
Answer & Solution
Answer: Option B
Solution:
$$\eqalign{ & {\text{Let principal = P}} \cr & \therefore {\text{amount = 3P}} \cr & {\text{Interest = 3P}} - {\text{P}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ = 2P}} \cr & {\text{According to the question,}} \cr & {\text{2P = }}\frac{{{\text{P}} \times {\text{R}} \times {\text{20}}}}{{100}} \cr & \Rightarrow {\text{R = 10% }} \cr} $$
Let after t years it will become double
$$\eqalign{ & {\text{Hence,}} \cr & {\text{Interest = 2P}} - {\text{P = P}} \cr & \Rightarrow {\text{P = }}\frac{{{\text{P}} \times 10 \times {\text{t}}}}{{100}} \cr & \Rightarrow {\text{t = 10 years}} \cr} $$
69
A person borrows some money for 5 years and ratio of loan amount : total interest amount is 5 : 2. Then find the ratio of loan amount : interest rate is equal to = ?
Discuss
Answer & Solution
Answer: Option D
Solution:
$$\eqalign{ & {\text{Loan Amount}}:{\text{Total Interest}} \cr & {\text{5}}:{\text{2}} \cr & {\text{Principal}} \to {\text{5}} \cr & {\text{Interest for 1 year}} \Rightarrow {\text{2}} \cr & {\text{Interest for 5 year}} \Rightarrow {\text{10}} \cr & {\text{10}} = \frac{{5 \times {\text{R}} \times 5}}{{100}} \cr & {\text{R}}\% = 40\% \cr & = \frac{{40}}{{100}} = \frac{2}{5} \cr & {\text{P}}:{\text{R}} = 5:\frac{2}{5} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\, = 25:2 \cr} $$
70
The effective annual rate of interest, corresponding to a nominal rate of 6% per annum payable half yearly is = ?
Discuss
Answer & Solution
Answer: Option D
Solution:
$$\eqalign{ & {\text{Half yearly rate}} \cr & {\text{ = }}\frac{6}{2} = 3\% \cr & {\text{Effective rate % }} \cr & {\text{ = 3}} + {\text{3}} + \frac{{3 \times 3}}{{100}} \cr & = 6.09\% \cr} $$