Answer & Solution
Answer: Option B
Solution:
$$\eqalign{
& {\text{Side of equilateral }}\Delta = 8{\text{ cm}} \cr
& {\text{In circle radius}} = \frac{a}{{2\sqrt 3 }} = \frac{8}{{2\sqrt 3 }} = \frac{4}{{\sqrt 3 }} \cr
& {\text{Circum radius}} = \frac{a}{{\sqrt 3 }} = \frac{8}{{\sqrt 3 }} \cr
& {\text{Area bounded by both circle is}} \cr
& = \pi \left\{ {{{\left( {\frac{8}{{\sqrt 3 }}} \right)}^2} - {{\left( {\frac{4}{{\sqrt 3 }}} \right)}^2}} \right\} \cr
& = \frac{{22}}{7}\left( {\frac{{64}}{3} - \frac{{16}}{3}} \right) \cr
& = \frac{{22}}{7}\left( {\frac{{48}}{3}} \right) \cr
& = \frac{{22 \times 16}}{7} \cr
& = 50\frac{2}{7}{\text{ c}}{{\text{m}}^2} \cr} $$
