ABCD is a parallelogram. BC is produced to Q such that BC = CQ. Then
A. area (ΔABC) = area (ΔDCQ)
B. area (ΔABC) > area (ΔDCQ)
C. area (ΔABC) < area (ΔDCQ)
D. area (ΔABC) ≠ area (ΔDCQ)
Answer: Option A
Solution (By Examveda Team)

In ΔABC & ΔDCQ
∠ABC = ∠DCQ
∠ACB = ∠DQC
BC = CQ
ΔABC ≅ ΔDCQ
ar ΔABC = ar ΔDCQ
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