Problems On Ages - Aptitude MCQ Questions and Solutions with Explanations

Answer: Option A

$$\eqalign{ & {\text{Let}}\,{\text{Ronit's}}\,{\text{present}}\,{\text{age}}\,{\text{be}}\,x\,{\text{years}}. \cr & {\text{Then,}}\,{\text{father's}}\,{\text{present}}\,{\text{age}}\, \cr & = \left( {x + 3x} \right)\,{\text{years}} \cr & = 4x\,{\text{years}} \cr & \therefore \left( {4x + 8} \right) = \frac{5}{2}\left( {x + 8} \right) \cr & \Rightarrow 8x + 16 = 5x + 40 \cr & \Rightarrow 3x = 24 \cr & \Rightarrow x = 8 \cr & {\text{Hence,}}\,{\text{required}}\,{\text{times}} \cr & = \frac{{ {4x + 16} }}{{ {x + 16} }} \cr & = \frac{{48}}{{24}} \cr & = 2 \cr} $$

Answer: Option A

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
⇒ 5x = 20
⇒ x = 4.
∴ Age of the youngest child = x = 4 years.

Answer: Option A

Let the son's present age be x years. Then, (38 - x) = x
⇒ 2x = 38.
⇒ x = 19.
∴ Son's age 5 years back (19 - 5) = 14 years.

Answer: Option D

Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.

∴ (2x + 2) + 2x + x = 27
⇒ 5x = 25
⇒ x = 5.
Hence, B's age = 2x = 10 years.

Answer: Option A

$$\eqalign{ & {\text{Let}}\,{\text{the}}\,{\text{present}}\,{\text{ages}}\,{\text{of}}\,{\text{Sameer}}\,{\text{and}}\,{\text{Anand}}\,{\text{be}}\, \cr & 5x\,{\text{years}}\,{\text{and}}\,4x\,{\text{years}}\,{\text{respectively}} \cr & {\text{Then,}}\,\frac{{5x + 3}}{{4x + 3}} = \frac{{11}}{9} \cr & \Rightarrow 9\left( {5x + 3} \right) = 11\left( {4x + 3} \right) \cr & \Rightarrow 45x + 27 = 44x + 33 \cr & \Rightarrow 45x - 44x = 33 - 27 \cr & \Rightarrow x = 6 \cr & \therefore {\text{Anand's}}\,{\text{present}}\,{\text{age}} \cr & = 4x \cr & = 24\,{\text{years}}\, \cr} $$