At a casino in Mumbai, there are 3 tables A, B and C. The payoffs at A is 10 : 1, at B is 20 : 1 and C is 30 :1. If a man bets Rs. 200 at each table and win at two of the tables, what is the maximum and minimum difference between his earnings can be ?

A. Rs. 4000

B. Rs. 4500

C. Rs. 2500

D. Rs. 2000

E. None of these

Answer: Option A

Solution(By Examveda Team)

Maximum earning will be only possible when he will won on the maximum yielding table
A → 10 : 1
B → 20 : 1
C → 30 : 1
i.e., he won B and C but lost on A
20 × 200 + 30 × 200 - 1 × 200 = 9800
Minimum earnings will be when he won on table A and B and lose on table 3
10 × 200 + 20 × 200 - 1 × 200 = 5800
Therefore, difference = 9800 - 5800 = Rs. 4000

Alternatively,
The difference,
= [(30 + 20 - 1) - (10 + 20 -1)] × 200
= Rs. 4000