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Changing the order of the integration in the double integral \[{\text{I}} = \int\limits_0^8 {\int\limits_{\frac{{\text{x}}}{4}}^2 {{\text{f}}\left( {{\text{x,}}\,{\text{y}}} \right){\text{dydx}}} } \]     leads to \[{\text{I}} = \int\limits_{\text{r}}^{\text{s}} {\int\limits_{\text{p}}^{\text{q}} {{\text{f}}\left( {{\text{x,}}\,{\text{y}}} \right){\text{dx dy}}} .} \]     What is q?

A. 4y

B. 16y2

C. x

D. 8

Answer: Option A


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