Changing the order of the integration in the double integral \[{\text{I}} = \int\limits_0^8 {\int\limits_{\frac{{\text{x}}}{4}}^2 {{\text{f}}\left( {{\text{x,}}\,{\text{y}}} \right){\text{dydx}}} } \] leads to \[{\text{I}} = \int\limits_{\text{r}}^{\text{s}} {\int\limits_{\text{p}}^{\text{q}} {{\text{f}}\left( {{\text{x,}}\,{\text{y}}} \right){\text{dx dy}}} .} \] What is q?
A. 4y
B. 16y2
C. x
D. 8
Answer: Option A

Join The Discussion