Coherent orthogonal binary FSK modulation is used to transmit two equiprobable symbol waveforms s1(t) = αcos2πf1t & s2(t) = αcos2πf2t1 where α = 4 mV. Assume an AWGN channel with two-sided noise power spectral density $$\frac{{{N_0}}}{2} = 0.5 \times {10^{ - 12}}W/Hz.$$ Using an optimal receiver and the relation $$Q\left( v \right) = \frac{1}{{\sqrt {2\pi } }}\int\limits_v^\infty {{\theta ^{\frac{{{u^2}}}{2}}}du,} $$ the bit error probability for a data rate of 500 kbps is
A. Q(2)
B. $$Q\left( {2\sqrt 2 } \right)$$
C. Q(4)
D. $$Q\left( {4\sqrt 2 } \right)$$
Answer: Option C
Related Questions on Digital Communication
A. Only 800 Hz component
B. 800 Hz and 900 Hz components
C. 800 Hz and 1000 Hz components
D. 800 Hz, 900 Hz and 100 Hz components
Increased pulse width in the flat top sampling, leads to
A. Attenuation of high frequencies in reproduction
B. Attenuation of low frequencies in reproduction
C. Greater aliasing errors in reproduction.
D. No harmful effects in reproduction
A. 16 Mbps
B. 100 Mbps
C. 600 Mbps
D. 6.4 Gbps
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