Computer A takes 3 minutes to process an input while computer B takes 5 minutes. If computers A, B and C can process an average of 14 inputs in one hour, how many minutes does computer C alone take to process one input ?

Solution(By Examveda Team)

Number of units processed by computer A in 1 minute
$$ = \frac{1}{3}$$
Number of units processed by computer B in 1 minute
$$ = \frac{1}{5}{\text{ }}$$
Number of units processed by computer A, B and C in 1 minute
$$\eqalign{ & = \frac{{14 \times 3}}{{60}} \cr & {\text{ = }}\frac{7}{{10}} \cr} $$
Number of units processed by computer C in 1 minute
$$\eqalign{ & = \frac{7}{{10}} - \left( {\frac{1}{3} + \frac{1}{5}} \right) \cr & = \frac{7}{{10}} - \frac{8}{{15}} \cr & = \frac{5}{{30}} \cr & = \frac{1}{6} \cr} $$
Hence, computer C takes 6 minutes to process one input alone.