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Data Interpretation MCQ Questions and Answers - Table Chart

Learn Table Chart Data Interpretation mcq question and answers with easy and logical explanations Page-9 section-1

Directions (1 - 5): Study the following table carefully and answer the question that follow:
Number of candidates (in lakhs) appearing in a Entrance Examination from six different Cities.
City A B C D E F
No. of Candidates 1.25 3.14 1.08 2.27 1.85 2.73
Ratio of Candidates Passing and Failing Within the City
City Ratio of Passing and Failing
A 7 : 3
B 5 : 3
C 4 : 5
D 1 : 3
E 3 : 2
F 7 : 5
1
The number of candidates appearing for the exam from City C is what per cent of the number of candidates appearing for the exam from City B? (rounded to nearest integer)
Discuss
Answer & Solution
$$\eqalign{ & \text{No. of candidates from city C} \cr & = 1.08\times100000 \cr & = 108000 \cr & \text{No. of candidates from city B} \cr & = 3.14\times100000 \cr & = 314000 \cr & \therefore \text{Required percentage} \cr & = \left(\frac{108000}{314000}\times100\right)\% \cr & = \left(\frac{108}{314}\times100\right)\% \cr & = \left(\frac{54}{157}\times100\right)\% \cr & = \frac{5400}{157}\% \cr & = 34.39\% \cr & \approx 34\% \cr} $$
2
What is the number of candidates passing the exam from city E?
Discuss
Answer & Solution
Number of candidates passing the exam from City E.
$$\eqalign{ & = 1.85\times100000\times\frac{3}{5} \cr & = 185000\times\frac{3}{5} \cr & = 37000\times3 \cr & = 111000 \cr} $$
3
The number of candidates passing the examination from City F is what per cent of the total number of candidates appearing from all the cities together? ( rounded off to two digits after the decimal)
Discuss
Answer & Solution
Total number of candidates from al the 5 cities
= {(1.25 + 3.14 + 1.08 + 2.27 + 1.85 + 2.73) × 100000}
= 12.32 × 100000
= 1232000
Number of candidates passing the exam from city F
$$\eqalign{ & = \frac{7}{12}\times2.73\times100000 \cr & = \frac{7\times273\times1000}{12} \cr & = 7\times91\times250 \cr & = 159250 \cr & \therefore \text{Required percentage} \cr & = \left(\frac{159250}{1232000}\times100\right)\% \cr & = \frac{15925}{1232}\% \cr & = 12.926\% \cr & \approx 12.93\% \cr} $$
4
What is the ratio of the number of candidates failing the exam from City D to that of those failing the exam from City A?
Discuss
Answer & Solution
$$\eqalign{ & \text{No. of candidates failing from city D} \cr & = \frac{3}{4}\times2.27\times100000 \cr & = \frac{3}{4}\times\frac{227}{100}\times100000 \cr & = 227\times750 \cr & \text{No. of candidates failing from city A} \cr & = \frac{3}{10}\times1.25\times100000 \cr & = \frac{3}{10}\times\frac{125}{100}\times100000 \cr & = 300\times125 \cr & \therefore \text{Required ratio} \cr & = \frac{227\times750}{300\times125} \cr & = \frac{227}{50} \cr & = 227:50 \cr} $$
5
Which city has the highest number of students failing the entrance exam?
Discuss
Answer & Solution
Number of failures from different cities:
$$\eqalign{ & \text{A}→ 1.25\times100000\times\frac{3}{10} \cr & \,\,\,\,\,\, = 37500 \cr & \text{B}→ 3.14\times100000\times\frac{3}{8} \cr & \,\,\,\,\,\, = \frac{314000\times3}{8} \cr & \,\,\,\,\,\, = 117750 \cr & \text{C}→ 1.08\times100000\times\frac{5}{9} \cr & \,\,\,\,\,\, = 108000\times\frac{5}{9} \cr & \,\,\,\,\,\, = 60000 \cr & \text{D}→ 2.27\times100000\times\frac{3}{4} \cr & \,\,\,\,\,\, = 227000\times\frac{3}{4} \cr & \,\,\,\,\,\, = 170250 \cr & \text{E}→ 1.85\times100000\times\frac{2}{5}\cr & \,\,\,\,\,\, = 185000\times\frac{2}{5} \cr & \,\,\,\,\,\, = 74000 \cr & \text{F}→ 2.73\times100000\times\frac{5}{12} \cr & \,\,\,\,\,\, = 273000\times\frac{5}{12} \cr & \,\,\,\,\,\, = 113750 \cr } $$
So,
The maximum number failures are from city D.