Determine Output void main() char p= hi friends p1 p1=p while(...

This question belongs to C Program C Miscellaneous

C Miscellaneous

Determine Output:

void main()
{
      char *p="hi friends", *p1;
      p1=p;
      while(*p!='\0') ++*p++;
      printf("%s", p1);
}

A) hi friends B) ij!gsjfoet C) hj grjeodt D) None of These

Answer & Solution

Correct Answer: Option B

++*p++ will be parse in the given order :
1. *p that is value at the location currently pointed by p will be taken
2. ++*p the retrieved value will be incremented
3. when ; is encountered the location will be incremented that is p++ will be executed.

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5 Comments

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Yousef Walid 2 years ago

The question should be
void main()
{
char p[]="hi friends", *p1;
p1=p;
while(*p1!='') ++*p1++;
printf("%s",p);
}
for the answer to be correct

WG KIM 7 years ago

The question should be modified as
{
char p[20] = "hi friends", * p1;
p1 = p;
while (*p1 != '') ++*p1++;
printf("%sn", p);
}

Abdelbadie Belmouhcine 9 years ago

Hello,
This code must provide a runtime error because p is pointed to a literal string, which is unmodifiable.
Thanks.

Abhishek Singh 9 years ago

Give full ans in brief !please.

Gurpreet Gandhi 9 years ago

P1 pointer is not effected by the moment of p1(they are copy of the same string hi friends) hence the answer should be hi friends , isn't it ??

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