Determine Output:
void main()
{
printf("%p", main);
}
void main()
{
printf("%p", main);
}
A. Error
B. make an infinite loop
C. Some address will be printed
D. None of These
Answer: Option C
Solution(By Examveda Team)
Function names are just addresses (just like array names are addresses). main() is also a function. So the address of function main will be printed. %p in printf() specifies that the argument is an address. They are printed as hexadecimal numbers.
Determine output:
void main()
{
int const *p=5;
printf("%d", ++(*p));
}
A. 6
B. 5
C. Garbage Value
D. Compiler Error
A. mmm nnn aaa
B. mmmm nnnn aaaa
C. Compiler Error
D. None of These
A. I hate Examveda
B. I love Examveda
C. Error
D. None of These
Determine Output:
void main()
{
static int var = 5;
printf("%d ", var--);
if(var)
main();
}
A. 5 5 5 5 5
B. 5 4 3 2 1
C. Infinite Loop
D. None of These
Join The Discussion