Determine Output:
void main()
{
int i=1, j=2;
switch(i)
{
case 1: printf("GOOD"); break;
case j: printf("BAD"); break;
}
}
void main()
{
int i=1, j=2;
switch(i)
{
case 1: printf("GOOD"); break;
case j: printf("BAD"); break;
}
}
A. GOOD BAD
B. GOOD
C. Compiler Error
D. None of These
Answer: Option C
Solution(By Examveda Team)
Compiler Error: Constant expression required in function main.
The case statement can have only constant expressions (this implies that we cannot use variable names directly so an error).
Note: Enumerated types can be used in case statements.
Related Questions on C Miscellaneous
Determine output:
void main()
{
int const *p=5;
printf("%d", ++(*p));
}
A. 6
B. 5
C. Garbage Value
D. Compiler Error
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B. mmmm nnnn aaaa
C. Compiler Error
D. None of These
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B. I love Examveda
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Determine Output:
void main()
{
static int var = 5;
printf("%d ", var--);
if(var)
main();
}
A. 5 5 5 5 5
B. 5 4 3 2 1
C. Infinite Loop
D. None of These
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