Determine Output:
void main()
{
int i=0;
for(;i++;printf("%d", i));
printf("%d", i);
}
void main()
{
int i=0;
for(;i++;printf("%d", i));
printf("%d", i);
}
A. 1
B. 11
C. 12
D. Error
Answer: Option A
Solution(By Examveda Team)
Before entering into the for loop checking condition is "evaluated". Here it evaluates to 0 (false) and comes out of the loop, and i is incremented (note the semicolon after the for loop).
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wouldn't the loop checking evaluate to 1 since 0 ++ is 1 then enter the loop
?