Examveda
Examveda

Determine Output:
void main()
{
      int i=-1, j=-1, k=0, l=2, m;
      m = i++ && j++ && k++ || l++;
      printf("%d %d %d %d %d", i, j, k, l, m);
}

A. 0 0 1 2 0

B. 0 0 1 3 0

C. 0 0 1 3 1

D. 0 0 0 2 1

Answer: Option C

Solution(By Examveda Team)

Logical operations always give a result of 1 or 0 . And also the logical AND (&&) operator has higher priority over the logical OR (||) operator. So the expression 'i++ && j++ && k++' is executed first. The result of this expression is 0 (-1 && -1 && 0 = 0). Now the expression is 0 || 2 which evaluates to 1 (because OR operator always gives 1 except for '0 || 0' combination- for which it gives 0). So the value of m is 1. The values of other variables are also incremented by 1.

Join The Discussion

Comments ( 1 )

  1. Sourabh Jain
    Sourabh Jain :
    3 months ago

    main()
    { int i = 0 , j = 1 , k =2 , l ;
    l = i && j++ && ++k ;
    printf ( “ %d %d %d %d ” , i , j , k , l ) ;
    }
    Ans: Output : 0 1 2 0
    why out put is not : 0 2 3 0

Related Questions on C Miscellaneous