ExamVeda
Login
Home
This question belongs to C Program C Miscellaneous
C Miscellaneous
?

Determine Output:
void main()
{
      int i=-1, j=-1, k=0, l=2, m;
      m = i++ && j++ && k++ || l++;
      printf("%d %d %d %d %d", i, j, k, l, m);
}

Answer & Solution
Correct Answer: Option C

Logical operations always give a result of 1 or 0 . And also the logical AND (&&) operator has higher priority over the logical OR (||) operator. So the expression 'i++ && j++ && k++' is executed first. The result of this expression is 0 (-1 && -1 && 0 = 0). Now the expression is 0 || 2 which evaluates to 1 (because OR operator always gives 1 except for '0 || 0' combination- for which it gives 0). So the value of m is 1. The values of other variables are also incremented by 1.

Examveda
Question posted by Examveda
Community

Join the Discussion

1 Comment
Sourabh Jain
Sourabh Jain 7 years ago
main()
{ int i = 0 , j = 1 , k =2 , l ;
l = i && j++ && ++k ;
printf ( “ %d %d %d %d ” , i , j , k , l ) ;
}
Ans: Output : 0 1 2 0
why out put is not : 0 2 3 0