Determine Output:
void main()
{
char *str1 = "abcd";
char str2[] = "abcd";
printf("%d %d %d", sizeof(str1), sizeof(str2), sizeof("abcd"));
}
void main()
{
char *str1 = "abcd";
char str2[] = "abcd";
printf("%d %d %d", sizeof(str1), sizeof(str2), sizeof("abcd"));
}
A. 2 5 5
B. 5 5 5
C. 2 4 5
D. 2 4 4
Answer: Option A
Solution(By Examveda Team)
In first sizeof, str1 is a character pointer so it gives you the size of the pointer variable. In second sizeof the name str2 indicates the name of the array whose size is 5 (including the '\0' termination character). The third sizeof is similar to the second one.
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Related Questions on C Miscellaneous
Determine output:
void main()
{
int const *p=5;
printf("%d", ++(*p));
}
A. 6
B. 5
C. Garbage Value
D. Compiler Error
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void main()
{
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if(var)
main();
}
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the output is 8 5 5