Determine Output void main() int i = abc(10) printf( d --i)...

This question belongs to C Program C Miscellaneous

C Miscellaneous

Determine Output:

void main()
{
      int i = abc(10);
      printf("%d", --i);
}
int abc(int i)
{
      return(i++);
}

A) 10 B) 9 C) 11 D) None of These

Answer & Solution

Correct Answer: Option B

"return(i++)", it will first return i and then increment it. i.e. 10 will be returned.

Question posted by Examveda

Community

Join the Discussion

4 Comments

Join the discussion

Poorvi Patil 4 years ago

it'll be 9
coz --i will be printed , value of i is 10 hence --i=9

Deependra Singh 5 years ago

the answer should be compilation error as the function abc() is not defined/declared before main(). The compiler will return unidenfitied abc() error.

WG KIM 7 years ago

I believe it happens compile error which needs the declaration before using a function.

Neha Yadav 8 years ago

wa t is the ans ???? is it 10 or 9 ?

Keep Learning

Related Questions on C Miscellaneous

Determine output:

void main()
{
      int const *p=5;
      printf("%d", ++(*p));
}

Determine Output:

void main()
{
      char s[]="man";
      int i;
      for(i=0; s[i]; i++)
            printf("%c%c%c%c ", s[i], *(s+i), *(i+s), i[s]);
}

Determine Output:

void main()
{
      float me = 1.1;
      double you = 1.1;
      if(me==you)
            printf("I hate Examveda");
      else
            printf("I love Examveda");
}

Determine Output:

void main()
{
      static int var = 5;
      printf("%d ", var--);
      if(var)
            main();
}