?
Determine Output:
Determine Output:
void main()
{
char a[]="12345";
int i = strlen(a);
printf("%d", ++i);
}
void main()
{
char a[]="12345";
int i = strlen(a);
printf("%d", ++i);
}
Answer & Solution
Correct Answer:
Option
B
The char array 'a' will hold the initialized string, whose length will be counted from 0 till the null character. Hence the 'i' will hold the value equal to 5, after the pre-increment in the printf statement, then 6 will be printed.
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