Determine Output:
void main()
{
int a[] = {10,20,30,40,50}, j, *p;
for(j=0; j<5; j++){
printf("%d" ,*a);
a++;
}
p = a;
for(j=0; j<5; j++){
printf("%d" ,*p);
p++;
}
}
void main()
{
int a[] = {10,20,30,40,50}, j, *p;
for(j=0; j<5; j++){
printf("%d" ,*a);
a++;
}
p = a;
for(j=0; j<5; j++){
printf("%d" ,*p);
p++;
}
}
A. 10 20 30 40 50 10 20 30 40 50
B. 10 20 30 40 50 Garbage Value
C. Error
D. None of These
Answer: Option C
Solution(By Examveda Team)
Compiler error: lvalue required
Error is in line with statement a++. The operand must be an lvalue and may be of any of scalar type for any operator, array name only when subscripted is an lvalue. Simply array name is a non-modifiable lvalue.
Determine output:
void main()
{
int const *p=5;
printf("%d", ++(*p));
}
A. 6
B. 5
C. Garbage Value
D. Compiler Error
A. mmm nnn aaa
B. mmmm nnnn aaaa
C. Compiler Error
D. None of These
A. I hate Examveda
B. I love Examveda
C. Error
D. None of These
Determine Output:
void main()
{
static int var = 5;
printf("%d ", var--);
if(var)
main();
}
A. 5 5 5 5 5
B. 5 4 3 2 1
C. Infinite Loop
D. None of These
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