Determine Output:
#include<stdio.h>
void main()
{
char s[]={'a','b','c','n','c','\0'};
char *p, *str, *str1;
p=&s[3];
str=p;
str1=s;
printf("%c", ++*p + ++*str1-32);
}
#include<stdio.h>
void main()
{
char s[]={'a','b','c','n','c','\0'};
char *p, *str, *str1;
p=&s[3];
str=p;
str1=s;
printf("%c", ++*p + ++*str1-32);
}A. N
B. P
C. M
D. None of These
Answer: Option C
Solution(By Examveda Team)
p is pointing to character '\n'. str1 is pointing to character 'a'.
++*p: "p is pointing to '\n' and that is incremented by one." the ASCII value of '\n' is 10. then it is incremented to 11. the value of ++*p is 11.
++*str1: "str1 is pointing to 'a' that is incremented by 1 and it becomes 'b'. ASCII value of 'b' is 98.
Both 11 and 98 is added and result is subtracted from 32.
i.e. (11+98-32) = 77("M").
This Question Belongs to C Program >> C Miscellaneous
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Comments ( 2 )
Determine output:
void main()
{
int const *p=5;
printf("%d", ++(*p));
}
A. 6
B. 5
C. Garbage Value
D. Compiler Error
A. mmm nnn aaa
B. mmmm nnnn aaaa
C. Compiler Error
D. None of These
A. I hate Examveda
B. I love Examveda
C. Error
D. None of These
Determine Output:
void main()
{
static int var = 5;
printf("%d ", var--);
if(var)
main();
}
A. 5 5 5 5 5
B. 5 4 3 2 1
C. Infinite Loop
D. None of These
For this question, 'c' should be removed at s[].
the value n is not 10 it is 109. i think it is not n it is